[Flatlander]

**WARNING** this is bound to get nerd'ed up here fast...

Kos, can you reword your above post to reflect which portions of my post you are talking about; I'm having a tough time following you.

I did make a mistake however, as voltage is equivalent to potential, where power is the 2-dimension unit representing the combination of both current and voltage.

Potential IS voltage, not equivalent to. The terms are use interchangeably, potential just makes more 'sense'. For instance, you rub your feet on the carpet and now have a static charge (voltage/potential)...you now have the 'potential' to shock the hell out of someone - assuming the other person is at a lower voltage/potential than you are. I haven't a clue what you mean by "2-dimension unit"...are you talking about scalars vs vectors???

In theory, DC motors do not drain an infinite amount of current. Every motor can be tested at a stall load to get the maximum current drained into the system.

That value is way past anything that the components of the AEG can hold for more than a few seconds. For all purposes and intend, the value is too large to be relevent. In this perspective, 100A in a system that can take at most 40A can be considered infinite.

When the system is powered by a battery that can deliver around 40-50A peak, it also can be considered infinite in the way that it is a lot above the physical limit of the components.

Not sure what you were trying to prove/disprove there.

You cannot push more current into an electrical system because current is a 1-dimension unit.

Again, you lost me there.

It represents the instantaneous amount of energy that flows in a device.

It's the amount of Coulombs that flow (not necessarily in a device) -> Amperes = Coulomb / second. Volt x Coulomb = Joule (joules is the unit of energy)

Voltage is a speed at which the current is moving, thus it can be "forced" faster into the device.

Sorry, but that makes no sense. The mechanical analogy to Voltage is Pressure (ie. PSI, kPa), and current is the fluid flow (ie. GPM, CFM). You can think of an electrical system exactly like a hydraulic system. Mathematically you also model both systems the same way (treat pressure like voltage and current like fluid flow).

The increase in current is only a side effect of the increase in power with the same load or resistance on the circuit.

Again, not sure what you meant here but I'm going to try and clarify things.

Power = Voltage x Current

Resistance of the system stays the same (ie. you don't upgrade/downgrade your AEG spring or change anything).

Now if you assume your theory that the motor only draws as much current as it NEEDS, then the power consumption would remain constant. So if this were true, if you increased the voltage you would see the current DECREASE to compensate to keep the power constant.

However it's proven that this isn't the case with our DC AEG motors. When you increase the voltage, the current also increases (thus more power). This is why we get higher ROF when we increase the voltage - assuming the cells have similar discharge characteristics.




Think of an AEG electrical system like an air powered angle grinder. If you want the grinder to spin faster, you need more power...so you need more air! To get more air you either:

a) increase the pressure (voltage) or
b) decrease the resistance - like use a larger diameter air hose - so more air (current) can flow.